如何计算每个单词在 txt 文件中出现的次数？

Question

Here is the assignment in detail: Write a complete python program which reads words from a file called trash.dat. Assume there is one word per line in the file. Output the count for each of the different words (case insensitive) in the file. For example a file with:

dog

Dog

cat

rat

Would output:

dog=2

cat=1

rat=1

Answer 1

You should go off and do your own homework to help you learn. But regardless, here is a solution.

#!/usr/bin/env python

dict = {}

with open("trash.dat", "rw") as f:
    for line in f:
        if line != "\n":
            if line.lower() in dict:
                dict[line.lower()] = dict[line.lower()] + 1
            else:
                dict[line.lower()] = 1

for x in dict:
    print "%s=" % x, dict[x]

Answer 2

#!python2

from collections import Counter

words = []

# load words to list
with open('trash.dat', 'r') as fp:
    for line in fp:
        if line != '\n':
            words.append(line.lower().rstrip())

# make a dictionary from the 'words' list
cnt = Counter(words)

# print out the key, value pairs
for k, v in cnt.items():
    print 'the count of ' + k + ' is: ' + str(v)

'''
# output
the count of rat is: 1
the count of dog is: 2
the count of cat is: 1
''''

Answer 3

This might help:

theWords = []
with open('fileName.dat', 'r') as file:
for every line in file:
    theWords.append(line.lower().rstrip("\n"))

print("Rat = " + theWords[1])
print("Dog = " + theWords[2])
print("Cat = " + theWords[3])

Every line in your file will be seperated.