仅在字符串后跟某些字符时替换字符串中的空格

Question

Im trying to replace all spaces in a string only if they are followed by a certain number os characters. My example:

DKR N872 DEMIR UN872 DENOX UZ319 MOPIL
DKR DEMIR DENOX MOPIL TRS N866 ELTOK

Current output:

DKR N872 DEMIR UN872 DENOX UZ319 MOPIL
DKR DCT DEMIR DENOX DCT MOPIL TRS N866 ELTOK

What i want is:

DKR N872 DEMIR UN872 DENOX UZ319 MOPIL
DKR DCT DEMIR DCT DENOX DCT MOPIL DCT TRS N866 ELTOK

My regex:

(?<fix1>[A-Z]{3,5}) (?<fix2>[A-Z]{3,5})

Replacement:
$1 DCT $2

As you can se, in my current output it skips the parts that's hase already been "involved" in the last replace. Like between DEMIR & DENOX.

Please help

Answer 1

您几乎就到了(?<fix1>[AZ]{3,5}) (?<fix2>(?=[AZ]{3,5}))用$1 DCT $2替换$1 DCT $2注意(?<fix1>[AZ]{3,5}) (?<fix2>(?=[AZ]{3,5}))运算符?=