通过降序返回记录编号进行排序

Question

I'm trying to rank users very simply by their reputation, which is stored as an int column in a MySQL table of users. In order to find out which users have the highest reputation from highest to lowest, I would do something like:

SELECT * FROM users ORDER BY reputation DESC 

Which would give me users ordered by highest reputation to lowest. Say user Tim shows up as the 3rd record. How do I return which # record he is in that order, ie his rank? This seems really simple but I'm drawing a blank on how to do it. Essentially I want the record # after ordering to say "he is the user with the third highest reputation". Alternatively, is this the wrong way to go about ranking?

I can specify a user in users by the column user_id and just mainly want to return the user's rank in one query, if possible.

I'm using Laravel as a framework if anyone knows a shortcut using that, but just generally with SQL would be fine too.

Answer 1

Are you looking for something like this?

set @rank:= 0;

SELECT (@rank:= @rank+ 1) AS Rank , users.* FROM users ORDER BY reputation DESC;

This will increment @rank for each resulting record. For a specific user use:

SELECT T.reprank 
FROM   (SELECT @rank := @rank + 1 AS reprank, 
               users.* 
        FROM   users, 
               (SELECT @rank := 0) rnk 
        ORDER  BY reputation DESC) AS T 
WHERE  id = 23 

Answer 2

This is similar to the Sam D answer, but it puts everything into a single query:

SELECT
  @rank := @rank + 1 AS RepRank,
  users.*
FROM users, (SELECT @rank := 0) rnk
ORDER BY reputation DESC;

To limit results to a specific user you'll need to do an outer query - there's really no way around it. Here's how (note that the inner query is the same as the query shown above):

SELECT * FROM (
  SELECT
    @rank := @rank + 1 AS RepRank,
    users.*
  FROM users, (SELECT @rank := 0) rnk
  ORDER BY reputation DESC
) RankedUsers
WHERE User_ID = 5