包含用于比较两个列表中元素的操作

Question

How can I compare two strings for contains operation? I tried using the in operator without success

list_1=['check value 1','check value 2']

list_2=['12312 check value 1 ','234 check value 2']

for ele in list_1:
    if ele in list_2:
        print 'element present'
    else:
        print 'abscent'

Result

abscent
abscent

I know we can compare them using another loop in list_2 and in over all elements. I am curious whether there is a better approach.

Answer 1

You'll need to test against every element in list_2 ; using membership on lists requires that the whole string is present in the list.

for partial in list_1:
    if any(partial in value for value in list_2):
        print 'element present'
    else:
        print 'absent'

Here the any() function , combined with a generator expression, at least stops searching as soon as a match has been found.

Answer 2

Your code needed just a little change :-)

list_1=['check value 1','check value 2']

list_2=['12312 check value 1 ','234 check value 2']

for ele in list_1:
    for list2_ele in list_2:
        if ele in list2_ele:
            print 'element present'
        else:
            print 'absent'

You just needed the second for loop :-)