Linux awk命令隔离

Question

If I had a file with hundreds of records, how do I isolate let's say the first 5 lines and display them using "awk"? I am trying to display a few lines from a file with several records of names, date etc.

Answer 1

Not sure what you like, since you have none input data or output example
If you like to print the 5 first line of a file using awk , you can do:

awk 'n {print;n--}' n=5 file

or just

awk 'NR<6' file

Answer 2

let's say the first 5 lines and display

Question is tagged for awk but head is what you need. Use the right tool for the job. Although you can reinvent the wheel with awk

head -5 <file_name>

Answer 3

希望这行得通：

awk 'FNR<=5' file