linux AWK命令与操作符

Question

i get below result on Linux awk command, ,i want to grep all with greater than this filed [360] . the filed name is $13

[4]
[440]
[360]
[3]
[434]
[3]
[439]
[590]

the result should be :

[440]
[434]
[439]
[590]

Answer 1

with awk:

awk '{a=$0;gsub("[\\[\\]]","",$13);if(int($13)>360) {print a;}}' filename

it will print all lines, that action processed with greater than 360 mills.

Answer 2

awk  '!/\[3..\]|\[.\]/' file

[440]
[434]
[439]
[590]

Not to print three hundred... or one unit.