如何通过URL过滤flask-peewee中的查询？

Question

I'd like to run the following query by flask-peewee ,

merchant_name LIKE 'seaside%'

SELECT * 
FROM  `merchant_details` 
WHERE  `merchant_name` LIKE  'seaside%'

Here is the return JSON of the below URL and I need to filter the merhcnat_name http://www.XXXXX.com/api/merchant_details/

http://www.XXXXX.com/api/merchant_details/?merchant_name__like=seaside (This is not working)

{
  "meta": {
    "model": "merchant_details",
    "next": "",
    "page": 1,
    "previous": ""
  },
  "objects": [
    {
      "merchant_name": "Seaside Grill",
      "city": "Santa Monica ",
      "zipcode": "90401",
      "long": "-118.4884742",
      "phone": "3102399844",
      "state": "CA",
      "updated_on": "2013-11-07 01:14:42",
      "lat": "34.0189893",
      "street_1": "406 Broadway",
      "street_2": "1",
      "merchant_id": "1",
      "id": "2"
    },
{
  "merchant_name": "Jack n'  Jill's",
  "city": "Santa Monica",
  "zipcode": "90401",
  "long": "-118.4937635",
  "phone": "3109873733",
  "state": "CA",
  "updated_on": "2013-11-08 08:20:29",
  "lat": "34.0173215",
  "street_1": "510 Santa Monica Blvd",
  "street_2": "1",
  "merchant_id": "48",
  "id": "32"
}
  ]
}

Answer 1

You should encode the url like this:

?merchant_name__like=seaside%25

You can get the encoded query string by urllib.urlencode({'merchant_name__like': 'seaside%'}) , ?merchant_name__like=seaside means LIKE seaside in sql.

Answer 2

You can use sqlalchemy-elasticquery that allow you make search like this:

?filters={ "merchant_nameseaside" : {"like" : "%seaside%"} }

and another custom filters.