如何通過URL過濾flask-peewee中的查詢？

Question

我想通過flask-peewee運行以下查詢，

merchant_name喜歡'seaside％'

SELECT * 
FROM  `merchant_details` 
WHERE  `merchant_name` LIKE  'seaside%'

這是以下URL的返回JSON，我需要過濾merhcnat_name http://www.XXXXX.com/api/merchant_details/

http://www.XXXXX.com/api/merchant_details/?merchant_name__like=seaside （這不起作用）

{
  "meta": {
    "model": "merchant_details",
    "next": "",
    "page": 1,
    "previous": ""
  },
  "objects": [
    {
      "merchant_name": "Seaside Grill",
      "city": "Santa Monica ",
      "zipcode": "90401",
      "long": "-118.4884742",
      "phone": "3102399844",
      "state": "CA",
      "updated_on": "2013-11-07 01:14:42",
      "lat": "34.0189893",
      "street_1": "406 Broadway",
      "street_2": "1",
      "merchant_id": "1",
      "id": "2"
    },
{
  "merchant_name": "Jack n'  Jill's",
  "city": "Santa Monica",
  "zipcode": "90401",
  "long": "-118.4937635",
  "phone": "3109873733",
  "state": "CA",
  "updated_on": "2013-11-08 08:20:29",
  "lat": "34.0173215",
  "street_1": "510 Santa Monica Blvd",
  "street_2": "1",
  "merchant_id": "48",
  "id": "32"
}
  ]
}

Answer 1

您應該這樣編碼網址：

?merchant_name__like=seaside%25

您可以通過urllib.urlencode({'merchant_name__like': 'seaside%'})獲得編碼的查詢字符串， ?merchant_name__like=seaside表示在sql中LIKE seaside 。

Answer 2

您可以使用sqlalchemy-elasticquery來進行如下搜索：

?filters={ "merchant_nameseaside" : {"like" : "%seaside%"} }

和另一個自定義過濾器