C / C ++将void *转换为int（*（））（int，...）;

Question

How can I cast void* to int ( * () ) (int,...) ?

The void* is coming from a dlsym . This code isn't compiling:

typedef  int ( *PSYS () ) (int,...);
PSYS getf =  (PSYS) dlsym(lib, "function" );

Answer 1

If the symbol is a function pointer your typedef may be wrong. Should be:

typedef int (*PSYS)(int, ...);

Answer 2

PSYS is the type of a function, not a pointer to a function. You want

typedef  int ( *PSYS () ) (int,...);
PSYS* getf =  (PSYS*) dlsym(lib, "function" );