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Scala读取文件并拆分并修改每一行

[英]Scala read file and split and modify each line

I'm new to Scala. 我是Scala的新手。 I want to read lines from a text file and split and make changes to each lines and output them. 我想从文本文件中读取行并拆分并对每行进行更改并输出它们。

Here is what I got: 这是我得到的:

 val pre:String = " <value enum=\""
 val mid:String = "\" description=\""
 val sur:String = "\"/>"

 for(line<-Source.fromFile("files/ChargeNames").getLines){
    var array = line.split("\"")
    println(pre+array(1)+mid+array(3)+sur);
 }

It works but in a Object-Oriented programming way rather than a Functional programming way. 它的工作原理是面向对象的编程方式,而不是函数式编程方式。

I want to get familiar with Scala so anyone who could change my codes in Functional programming way? 我想熟悉Scala,以便任何能够以函数式编程方式更改代码的人?

Thx. 谢谢。

One traversal and no additional memory 一次遍历,没有额外的记忆

 Source
  .fromFile("files/ChargeNames")
  .getLines
  .map { line =>
    //do stuff with line like
    line.replace('a', 'b')
  }
  .foreach(println)

Or code which is a little bit faster, according to @ziggystar @ziggystar表示 ,代码更快一点

Source
  .fromFile("files/ChargeNames")
  .getLines
  .foreach { line =>
    //do stuff with line like
    println(line.replace('a', 'b'))
  }
val ans = for (line <- Source.fromFile.getLines) yield (line.replace('a', 'b')
ans foreach println

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