Bash逐行读取文件，按选项卡拆分，发送到Java应用程序

Question

I want to read from a file line by line, then construct a args string and then use this string to start an java application.

The file test.txt contains for example this lines, columns are tab separated:

abc def ghj kln

asd ss fdf twe

#!/bin/bash
IFS=$'\n'
while read k d a m s
do
    echo java -jar test.jar -k $k -d $d -a $a -m $m -s $s
done < test.txt

unfortunatly it does not work. bash output is broken:

-k abc def ghj kln -d -a -m -s

Answer 1

You say the columns are tab separated, so you should use \\t for IFS instead of \\n which means newline:

IFS=$'\t'

(Assuming that each line of the input contains the values for k , d , a , m , s separated by tabs).

Answer 2

You just have to change your IFS to separate on tabs \\t rather then new line \\n :

#!/bin/bash
while IFS=$'\t' read k d a m s
do
    echo java -jar test.jar -k "$k" -d "$d" -a "$a" -m "$m" -s "$s"
done < test.txt