替换RegEx出现的Java

Question

I have a string in Java like this:

REF([123],[456],[78]),REF([789],[456],[12]),{111},REF([8069],[8098],[56])

I need to remove all the third occurring digits inside all the REFs. Meaning I need to remove [78], [12] and [56] (starting from the second comma till before the closing brackets) from the string so that I get this following output:

REF([123],[456]),REF([789],[456]),{111},REF([8069],[8098])

What should my regex be?

Answer 1

String result = subject.replaceAll(
    "(?xi)(      # Match and capture in group 1:\n" +
    "REF\\(      # REF(\n" +
    "\\[\\d+\\], # a number in brackets, comma,\n" +
    "\\[\\d+\\]  # a number in brackets\n" +
    ")           # End of capturing group\n" +
    ",\\[\\d+\\] # Match a comma and a third number in brackets", "$1");