[英]How to get the reference to newly constructed instance in expression tree c#
Is It possible to get the reference to the PositionViewModel
in the following expression tree: 是否可以在以下表达式树中获取对
PositionViewModel
的引用:
public static Expression<Func<Model, ViewModel>> ToViewModel
{
get
{
return x => new PositionViewModel
{
Id = x.Id,
Name = x.Name,
Employees = x.Employees.Select(e => new Employee
{
Id = e.Id,
Name = e.Name,
Position = ??? // reference to PositionViewModel
}).ToList()
};
}
}
I think it is, because EF does that. 我认为是,因为EF做到了。 Any suggestions?
有什么建议么?
Edit: Forgot to mention that "Postition" is of type ViewModel. 编辑:忘了提到“Postition”是ViewModel类型。
I would spontaneously do it in steps: 我会自发地分步进行:
public static Expression<Func<Model, ViewModel>> ToViewModel
{
get
{
return x => GetViewModel(x);
}
}
public ViewModel GetViewModel(Model x)
{
var vm = new PositionViewModel
{
Id = x.Id,
Name = x.Name
};
vm.Employees = x.Employees.Select(p => new Employee
{
Id = p.Id,
Name = p.Name,
Position = vm
}).ToList();
return vm;
}
This way you can still wrap this up as an expression tree. 这样你仍然可以将它作为表达式树包装起来。
What you could do is to use the fact that Employees
is a property, so you can add any code you want to its setter. 您可以做的是使用
Employees
属性的事实,因此您可以将任何代码添加到其setter中。 Something like: 就像是:
private IList<Employee> employees;
public IList<Employee> Employees
{
get
{
return employees;
}
set
{
employees = value;
foreach (var employee in employees)
{
employee.Position = this;
}
}
}
With this, you don't need to do anything in your expression, and the Position
will be set automatically. 这样,您不需要在表达式中执行任何操作,并且将自动设置
Position
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.