遍历JSON数组

Question

I just got a jQuery AJAX call to function and now I am having trouble parsing the value that I am returning. I am working with a mysql database and returning an php array() like so to my jQuery AJAX function: echo json_encode($reservationArray);

Now, when I append this to my page in a simple div tag this is the result:

[{"reservation_id":"3","available":"0","lock":"0","restaurant":"2","date_made":"2013-12-09 18:39:52","date_of":"2014-01-02 00:00:00","time":"08:30:00","guests":"5","user":"0"},{"reservation_id":"4","available":"0","lock":"0","restaurant":"2","date_made":"2013-12-09 18:40:15","date_of":"2014-01-02 00:00:00","time":"08:00:00","guests":"7","user":"0"}]

I believe this is a proper JSON (Please, correct me if I am wrong). I have tried just about every method of accessing the data and cannot. Below is the approach that I am taking, to construct a new block of code, a bunch of rows - one per reservation (I have shortened the string for this example).

EDITED:

function my_ajax(rest_id){
    $.ajax({
      url: 'change_restaurant.php',
      type: 'POST',
      data: {'action': 'get-reservations', 'rest_id': rest_id},
      cache: false,
      success: function(json) {
       $.each(json, function(i, item) {
        if(typeof item == 'object') {
        newhtml += '<div>Restaurant Name :'+item.reservation_id+' Reservation Date: '+item.restaurant+'</div>'
        } 
        else {
          return false;
        }
      })

      $('#reservation-table').append(newhtml);

      },
      error: function(xhr, desc, err) {
        console.log(xhr + "\n" + err);
      }
    });

  }

Answer 1

I believe this is a proper JSON (Please, correct me if I am wrong).

It seems that the JSON your receiving is not the correct document. As Pointy said in the comments, nowhere are there fields "name" or "date".

[{
        "reservation_id" : "3",
        "available" : "0",
        "lock" : "0",
        "restaurant" : "2",
        "date_made" : "2013-12-09 18:39:52",
        "date_of" : "2014-01-02 00:00:00",
        "time" : "08:30:00",
        "guests" : "5",
        "user" : "0"
    }, {
        "reservation_id" : "4",
        "available" : "0",
        "lock" : "0",
        "restaurant" : "2",
        "date_made" : "2013-12-09 18:40:15",
        "date_of" : "2014-01-02 00:00:00",
        "time" : "08:00:00",
        "guests" : "7",
        "user" : "0"
    }
]

You need to modify your PHP code to perform a query that joins data from reservations and restaurants .

Answer 2

You also have not instructed jQuery to expect JSON in return. It may be parsing as string. Note the dataType option.

function my_ajax(rest_id){
    $.ajax({
      url: 'change_restaurant.php',
      type: 'POST',
      data: {'action': 'get-reservations', 'rest_id': rest_id},
      dataType: "json", // EXPECT JSON
      cache: false,
      success: function(json) {
       $.each(json, function(i, item) {
        if(typeof item == 'object') {
        newhtml += '<div>Restaurant Name :'+item.reservation_id+' Reservation Date: '+item.restaurant+'</div>'
        } 
        else {
          return false;
        }
      })

      $('#reservation-table').append(newhtml);
      ,
      error: function(xhr, desc, err) {
        console.log(xhr + "\n" + err);
      }
    });

  }