[英]Json.NET deserializing object returns null
I would like to deserialize a string o JSON and output data on a string: 我想反序列化字符串o JSON并输出字符串数据:
public class Test
{
public int id { get; set; }
public string name { get; set; }
public long revisionDate { get; set; }
}
private void btnRetrieve_Click(object sender, EventArgs e)
{
string json = @"{""Name"":{""id"":10,""name"":""Name"",""revisionDate"":1390293827000}}";
var output = JsonConvert.DeserializeObject<Test>(json);
lblOutput.Text = output.name;
}
This is intended to output the name
property of the string json
. 这是为了输出字符串json
的name
属性。 However, it returns nothing. 但是,它什么也没有返回。
The JSON you posted can be deserialized into an object which has a Name
propery of type Test
, not into a Test
instance. 您发布的JSON可以反序列化为一个对象,该对象具有Test
类型的Name
属性,而不是Test
实例。
This 这个
string json = @"{""id"":10,""name"":""Name"",""revisionDate"":1390293827000}";
would be a representation of a Test
instance. 将是Test
实例的表示。
Your JSON may be deserialized into something like this: 你的JSON可能被反序列化为这样的东西:
public class Test
{
public int id { get; set; }
public string name { get; set; }
public long revisionDate { get; set; }
}
public class Foo
{
public Test Name { get; set; }
}
// ...
var output = JsonConvert.DeserializeObject<Foo>(json);
lblOutput.Text = output.Name.name;
Valid json for Test class is below Test类的有效json如下所示
{ "Name": { "id": 10, "name": "Name", "revisionDate": 1390293827000 } } {“Name”:{“id”:10,“name”:“Name”,“revisionDate”:1390293827000}}
and Also your json is in containg more data then only test class so you can also use like 而且你的json正在包含更多数据,然后只有测试类,所以你也可以使用like
Dictionary<string,Test> dictionary= JsonConvert.DeserializeObject<Dictionary<string,Test>>(json);
Test oputput=dictionary["Name"];
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