[英]substract integer value from datetime field
I want to subtract an integer value from a datetime
field. 我想从
datetime
字段中减去一个整数值。 Here date_joined
is a datetime
field and age is an integer field. 这里
date_joined
是datetime
字段,age是整数字段。
views.py views.py
def index(request):
profiles = profiles.objects.all()
for profile in profiles:
age = person.age
date_joined = person.date_joined
date_of_birth = date_joined - age
p = date_of_birth(date_of_birth = date_of_birth,activated = 1)
p.save()
models.py models.py
class profiles(models.Model):
date_joined = models.DateTimeField (max_length=1)
age = models.IntegerField()
Use: 采用:
date_joined - (datetime.timedelta(365) * age)
To subtract age
years from date_joined
. 从
date_joined
减去age
。
Just a note that this is a good quick-and-dirty solution, but is not very robust. 请注意,这是一个很好的快捷解决方案,但不是很可靠。 Consider the following output:
考虑以下输出:
>>> datetime.datetime(2013, 12, 12) - datetime.timedelta(365) * 15
datetime.datetime(1998, 12, 16, 0, 0)
As you can see, because of leap years (years that actually have 366 days), the result is 4 days after the date we actually wanted. 如您所见,由于leap年(实际上有366天的年份),结果是我们实际想要的日期之后的4天。 A more robust solution would be:
一个更强大的解决方案是:
date_joined.replace(year = date_joined.year - age)
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