[英]Using fnmatch.fnmatch(path, “*”) - does it match everything?
I have inherited some code that uses os.walk to traverse sections of the file system. 我继承了一些使用os.walk遍历文件系统部分的代码。
for (dirpath, _, filenames) in os.walk(blahblah):
reldir = dirpath[len(base)+1:]
if fnmatch(reldir, './lost+found'):
continue
for path in filenames:
if fnmatch.fnmatch(path, "*"):
...
I am at a loss to understand the point of using fnmatch to match against "*", is there something that this will not match? 我无法理解使用fnmatch与“*”匹配的问题,是否存在不匹配的内容?
I ran a few tests with ".", "..", ".hidden", "normal.name", "normal"
and similar, but nothing seems to be filtered out. 我用
".", "..", ".hidden", "normal.name", "normal"
等进行了一些测试,但似乎没有任何过滤掉。
I can't see anything in the documentation, and I'm guessing the line was added for a reason, can anyone enlighten me? 我在文档中看不到任何内容,我猜这条线是有原因的,有人可以启发我吗?
Yes, it matches everything. 是的,它符合一切。 If you trace through the source code for
fnmatch.fnmatch
, it boils down to a regex match on the pattern 如果你追踪
fnmatch.fnmatch
的源代码,它归结为模式的正则表达式匹配
In [4]: fnmatch.translate('*')
Out[4]: '.*\\Z(?ms)'
That matches 0-or-more characters followed by the end-of-string ( \\Z
), with the MULTILINE and DOTALL flags on. 匹配0或更多字符后跟字符串结尾(
\\Z
),并打开MULTILINE和DOTALL标志。 That will match any string. 这将匹配任何字符串。
Maybe at some point the line 也许在某些时候这条线
if fnmatch.fnmatch(path, "*"):
used a more complicated pattern, but was later changed to "*"
instead of omitting the check. 使用了更复杂的模式,但后来改为
"*"
而不是省略检查。 But that's just speculation. 但那只是猜测。
In any case, the if-condition
could be removed, since it is always True. 在任何情况下,可以删除
if-condition
,因为它始终为True。
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