从xml文件解析属性

Question

I'm trying to parse the following:

<?xml version="1.0" encoding="utf-8"?>
<GC>
  <CREATED>01/23/2014 16:10:18</CREATED>
  <DATA>
    <CONTAINER name="home" type="xml" version="1.1.0.0">
      <HEADER>
        <ATTRIBUTE name="lang" value="EN" />
        <ATTRIBUTE name="destination" value="UK" />
      </HEADER>
    </CONTAINER>
  </DATA>
</GC>

How do I go about finding the value when name="lang" ?

So far I have this:

XmlDocument Doc = new XmlDocument();
Doc.Load(@path);
XmlNode node = Doc.DocumentElement.SelectSingleNode("/GC/DATA/CONTAINER/HEADER/ATTRIBUTE/NAME");
string SI = node.Attributes["lang"].InnerText;

Doesn't seem to work unfortunately, could use some help. Many thanks.

Answer 1

With using LINQ to XML you can get it like this:

XDocument xDoc = XDocument.Load("path");
var element = xDoc.Descendans("ATTRIBUTE").First();
var nameAttribute = (string)element.Attribute("name");

Answer 2

This will get you the value of the attribute in the ATTRIBUTE tag which has name == lang:

XmlDocument Doc = new XmlDocument();
Doc.Load(@path);
XmlNode node = Doc.DocumentElement.SelectSingleNode("/GC/DATA/CONTAINER/HEADER/ATTRIBUTE[@name='lang']");
string SI = node.Attributes["value"].InnerText;

Answer 3

    XmlNode node = Doc.DocumentElement.SelectSingleNode("/GC/DATA/CONTAINER/HEADER/ATTRIBUTE[@name='lang']");
    string SI = node.Attributes["value"].Value;

Answer 4

This will do it:

XmlNode node = 
 Doc.SelectSingleNode("/GC/DATA/CONTAINER/HEADER/ATTRIBUTE[@name = 'lang']/@value");
string SI = node.InnerText;

And I would advise using a null check:

XmlNode node = 
 Doc.SelectSingleNode("/GC/DATA/CONTAINER/HEADER/ATTRIBUTE[@name = 'lang']/@value");
string SI = null;
if(node != null)
{
    SI = node.InnerText;
}