如何从 JavaScript 关联数组中删除对象？

Question

Suppose I have this code:

var myArray = new Object();
myArray["firstname"] = "Bob";
myArray["lastname"] = "Smith";
myArray["age"] = 25;

Now if I wanted to remove "lastname"?....is there some equivalent of myArray["lastname"].remove() ?

(I need the element gone because the number of elements is important and I want to keep things clean.)

Answer 1

Objects in JavaScript can be thought of as associative arrays, mapping keys (properties) to values.

To remove a property from an object in JavaScript you use the delete operator:

const o = { lastName: 'foo' }
o.hasOwnProperty('lastName') // true
delete o['lastName']
o.hasOwnProperty('lastName') // false

Note that when delete is applied to an index property of an Array , you will create a sparsely populated array (ie. an array with a missing index).

When working with instances of Array , if you do not want to create a sparsely populated array - and you usually don't - then you should use Array#splice or Array#pop .

Note that the delete operator in JavaScript does not directly free memory. Its purpose is to remove properties from objects. Of course, if a property being deleted holds the only remaining reference to an object o , then o will subsequently be garbage collected in the normal way.

Using the delete operator can affect JavaScript engines' ability to optimise code .

Answer 2

All objects in JavaScript are implemented as hashtables/associative arrays. So, the following are the equivalent:

alert(myObj["SomeProperty"]);
alert(myObj.SomeProperty);

And, as already indicated, you "remove" a property from an object via the delete keyword, which you can use in two ways:

delete myObj["SomeProperty"];
delete myObj.SomeProperty;

Hope the extra info helps...

Answer 3

None of the previous answers address the fact that JavaScript does not have associative arrays to begin with - there is no array type as such, see typeof .

What JavaScript has, are object instances with dynamic properties. When properties are confused with elements of an Array object instance then Bad Things™ are bound to happen:

Problem

var elements = new Array()

elements.push(document.getElementsByTagName("head")[0])
elements.push(document.getElementsByTagName("title")[0])
elements["prop"] = document.getElementsByTagName("body")[0]

console.log("number of elements: ", elements.length)   // Returns 2
delete elements[1]
console.log("number of elements: ", elements.length)   // Returns 2 (?!)

for (var i = 0; i < elements.length; i++)
{
   // Uh-oh... throws a TypeError when i == 1
   elements[i].onmouseover = function () { window.alert("Over It.")}
   console.log("success at index: ", i)
}

Solution

To have a universal removal function that does not blow up on you, use:

Object.prototype.removeItem = function (key) {
   if (!this.hasOwnProperty(key))
      return
   if (isNaN(parseInt(key)) || !(this instanceof Array))
      delete this[key]
   else
      this.splice(key, 1)
};

//
// Code sample.
//
var elements = new Array()

elements.push(document.getElementsByTagName("head")[0])
elements.push(document.getElementsByTagName("title")[0])
elements["prop"] = document.getElementsByTagName("body")[0]

console.log(elements.length)                        // Returns 2
elements.removeItem("prop")
elements.removeItem(0)
console.log(elements.hasOwnProperty("prop"))        // Returns false as it should
console.log(elements.length)                        // returns 1 as it should

Answer 4

That only deletes the object, but it still keeps the array length the same.

To remove the element from the array, you need to do something like:

array.splice(index, 1);

Answer 5

While the accepted answer is correct, it is missing the explanation why it works.

First of all, your code should reflect the fact that this is not an array:

var myObject = new Object();
myObject["firstname"] = "Bob";
myObject["lastname"] = "Smith";
myObject["age"] = 25;

Note that all objects (including Array s) can be used this way. However, do not expect for standard JavaScript array functions (pop, push, etc.) to work on objects!

As said in accepted answer, you can then use delete to remove the entries from objects:

delete myObject["lastname"]

You should decide which route you wish to take - either use objects (associative arrays / dictionaries) or use arrays (maps). Never mix the two of them.

Answer 6

There is an elegant way in the Airbnb Style Guide to do this (ECMAScript 7):

const myObject = {
  a: 1,
  b: 2,
  c: 3
};
const { a, ...noA } = myObject;
console.log(noA); // => { b: 2, c: 3 }

Copyright: https://codeburst.io/use-es2015-object-rest-operator-to-omit-properties-38a3ecffe90

Answer 7

As other answers have noted, you are not using a JavaScript array, but a JavaScript object, which works almost like an associative array in other languages except that all keys are converted to strings. The new Map stores keys as their original type.

If you had an array and not an object, you could use the array's .filter function, to return a new array without the item you want removed:

var myArray = ['Bob', 'Smith', 25];
myArray = myArray.filter(function(item) {
    return item !== 'Smith';
});

If you have an older browser and jQuery, jQuery has a $.grep method that works similarly:

myArray = $.grep(myArray, function(item) {
    return item !== 'Smith';
});

Answer 8

Use method splice to completely remove an item from an object array:

Object.prototype.removeItem = function (key, value) {
    if (value == undefined)
        return;

    for (var i in this) {
        if (this[i][key] == value) {
            this.splice(i, 1);
        }
    }
};

var collection = [
    { id: "5f299a5d-7793-47be-a827-bca227dbef95", title: "one" },
    { id: "87353080-8f49-46b9-9281-162a41ddb8df", title: "two" },
    { id: "a1af832c-9028-4690-9793-d623ecc75a95", title: "three" }
];

collection.removeItem("id", "87353080-8f49-46b9-9281-162a41ddb8df");

Answer 9

You are using Object, and you don't have an associative array to begin with. With an associative array, adding and removing items goes like this:

    Array.prototype.contains = function(obj)
    {
        var i = this.length;
        while (i--)
        {
            if (this[i] === obj)
            {
                return true;
            }
        }
        return false;
    }


    Array.prototype.add = function(key, value)
    {
        if(this.contains(key))
            this[key] = value;
        else
        {
            this.push(key);
            this[key] = value;
        }
    }


    Array.prototype.remove = function(key)
    {
        for(var i = 0; i < this.length; ++i)
        {
            if(this[i] == key)
            {
                this.splice(i, 1);
                return;
            }
        }
    }



    // Read a page's GET URL variables and return them as an associative array.
    function getUrlVars()
    {
        var vars = [], hash;
        var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&');

        for(var i = 0; i < hashes.length; i++)
        {
            hash = hashes[i].split('=');
            vars.push(hash[0]);
            vars[hash[0]] = hash[1];
        }

        return vars;
    }


    function ForwardAndHideVariables() {
        var dictParameters = getUrlVars();

        dictParameters.add("mno", "pqr");
        dictParameters.add("mno", "stfu");

        dictParameters.remove("mno");


        for(var i = 0; i < dictParameters.length; i++)
        {
            var key = dictParameters[i];
            var value = dictParameters[key];
            alert(key + "=" + value);
        }
        // And now forward with HTTP-POST
        aa_post_to_url("Default.aspx", dictParameters);
    }


    function aa_post_to_url(path, params, method) {
        method = method || "post";

        var form = document.createElement("form");

        // Move the submit function to another variable
        // so that it doesn't get written over if a parameter name is 'submit'
        form._submit_function_ = form.submit;

        form.setAttribute("method", method);
        form.setAttribute("action", path);

        for(var i = 0; i < params.length; i++)
        {
            var key = params[i];

            var hiddenField = document.createElement("input");
            hiddenField.setAttribute("type", "hidden");
            hiddenField.setAttribute("name", key);
            hiddenField.setAttribute("value", params[key]);

            form.appendChild(hiddenField);
        }

        document.body.appendChild(form);
        form._submit_function_(); // Call the renamed function
    }

Answer 10

You can remove an entry from your map by explicitly assigning it to 'undefined'. As in your case:

myArray["lastname"] = undefined;

Answer 11

If, for whatever reason, the delete key is not working (like it wasn't working for me), you can splice it out and then filter the undefined values:

// To cut out one element via arr.splice(indexToRemove, numberToRemove);
array.splice(key, 1)
array.filter(function(n){return n});

Don't try and chain them since splice returns removed elements;

Answer 12

如果您的项目中有Underscore.js依赖项，这将非常简单 -

_.omit(myArray, "lastname")

Answer 13

We can use it as a function too. Angular throws some error if used as a prototype. Thanks @HarpyWar. It helped me solve a problem.

var removeItem = function (object, key, value) {
    if (value == undefined)
        return;

    for (var i in object) {
        if (object[i][key] == value) {
            object.splice(i, 1);
        }
    }
};

var collection = [
    { id: "5f299a5d-7793-47be-a827-bca227dbef95", title: "one" },
    { id: "87353080-8f49-46b9-9281-162a41ddb8df", title: "two" },
    { id: "a1af832c-9028-4690-9793-d623ecc75a95", title: "three" }
];

removeItem(collection, "id", "87353080-8f49-46b9-9281-162a41ddb8df");

Answer 14

By using the "delete" keyword, it will delete the array element from array in JavaScript.

For example,

Consider following statements.

var arrayElementToDelete = new Object();

arrayElementToDelete["id"]           = "XERTYB00G1";
arrayElementToDelete["first_name"]   = "Employee_one";
arrayElementToDelete["status"]       = "Active";

delete arrayElementToDelete["status"];

The last line of the code will remove the array element whose key is "status" from the array.

Answer 15

var myArray = newmyArray = new Object();
myArray["firstname"] = "Bob";
myArray["lastname"] = "Smith";
myArray["age"] = 25;

var s = JSON.stringify(myArray);

s.replace(/"lastname[^,}]+,/g, '');
newmyArray = JSON.parse(p);

Without looping/iterates we get the same result.

Answer 16

For "Arrays":

If you know the index:

array.splice(index, 1);

If you know the value:

function removeItem(array, value) {
    var index = array.indexOf(value);
    if (index > -1) {
        array.splice(index, 1);
    }
    return array;
}

The most upvoted answer for delete works well in case of objects but not for the real arrays. If I use delete it removes elements from loops but keeps the element as empty and length of array wont change. This may be a problem in some scenarios.

For example, if I do myArray.toString() on myArray after removal via delete , it creates an empty entry, ie ,, .

Answer 17

The only working method for me:

function removeItem (array, value) {
    var i = 0;
    while (i < array.length) {
        if(array[i] === value) {
            array.splice(i, 1);
        } else {
            ++i;
        }
    }
    return array;
}

Usage:

var new = removeItem( ["apple","banana", "orange"],  "apple");
// ---> ["banana", "orange"]

Answer 18

You can do the following if you want a more functional and elegant approach:

const o = { firstName: "foo", lastName: "bar" };
const { lastName, ...removed } = o;
lastName // bar
removed // { firstName: "foo" }

Not that the value of removed will be undefined if there are no items left in the object.