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从32位地址闪存中读取一个double

[英]Read a double from 32-bit address flash memory

I have a 32-bit microcontroller and have just written a double to the flash memory. 我有一个32位微控制器,并且刚刚向闪存中写入了两倍。 I now want to read the double back from memory, but I am doing something illegal as the microcontroller goes to the hard fault handler. 现在,我想从内存中读取double,但是当微控制器进入硬故障处理程序时,我在做非法的事情。

First I tried: 首先,我尝试了:

double Flash_Read64(uint32_t address)
{
    return *((double *) address);
}

but this did not work. 但这没有用。 Is it because address is 32-bit and the (double *) expect a 64-bit? 是因为地址是32位并且(double *)期望是64位吗?

I then tried: 然后,我尝试:

double Flash_Read64(uint32_t address)
{
    uint64_t temp;
    double * tempPtr = (double *) &temp;

    //Increment address.
    address += 4;

    //Get MSB.
    temp = (*((uint32_t *) (address)));

    //Shift MSB to upper half.
    temp = (temp << 32);

    //Decrement address.
    address -= 4;

    //Get LSB.
    temp |= (*((uint32_t *) address));

    return *tempPtr;
}

but still not working. 但仍然无法正常工作。

Any suggestions? 有什么建议么?

EDIT: 编辑:

bool_t Flash_Write64Address(uint32_t address, double data)
{
    uint32_t MSB, LSB;
    uint32_t * tempPtr = (uint32_t *) &data;

    //Get LSB.
    LSB = tempPtr[0];

    //Write LSB to flash.
    flashStatus = FLASH_ProgramWord(address, LSB);
    if(flashStatus != FLASH_COMPLETE)
    {
        DEBUG("Failed to write to flash at address: %u", (unsigned int) address);
        return FALSE;
    }

    //Increment address.
    address += 4;

    //Get MSB.
    MSB =  tempPtr[1];

    //Write MSB to flash.
    flashStatus = FLASH_ProgramWord(address, MSB);
    if(flashStatus != FLASH_COMPLETE)
    {
        DEBUG("Failed to write to flash at address: %u", (unsigned int) address);
        return FALSE;
    }

    return TRUE;
}

To simplify and avoid alignment issues (which I think it is the alignment issue that is causing grief.) 为了简化和避免对齐问题(我认为正是对齐问题引起了悲伤。)

typedef union {
  double d;
  uint32_t u[2];
} Xlate;

bool_t Flash_Write64Address(uint32_t address, double data) {
   Xlate x;
   x.d = data;
   for (int i=0; i < 2; i++) {
     int flashStatus = FLASH_ProgramWord(address, x.u[i]);
     address += 4;
     if(flashStatus != FLASH_COMPLETE) {
        return FALSE;
     }
   return TRUE;
   }

double Flash_Read64(uint32_t address) {
  Xlate x;
  x.u[0] = *((uint32_t *) address);
  x.u[1] = *((uint32_t *) (address + 4));
  return x.d;
}

[Edit] [编辑]
I am supposing that address represents an address with quad-byte alignment (its least 2 bits are 0). 我假设该address表示一个四字节对齐的地址(至少2位为0)。 If address did not have 8-byte alignment (its least 3 bits are 0) and a double access required it, then 如果address没有8-byte alignment (至少3位为0),并且需要double访问,则

return *((double *) address);
// or 
return *tempPtr;

would cause a bus fault. 会导致总线故障。 If this is true, the above code should handle this issue. 如果是这样,则上面的代码应处理此问题。
Alternatively code could insure address has 8-byte alignment . 或者,代码可以确保address具有8-byte alignment

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