如何结合构建类型和风格来获得构建变体调试<Flavor>
[英]How combine build type and flavor to get a build variant debug<Flavor>
问题描述
Is there a way to combine build type and flavor to get build variant such that resources would be taken from most specific res folder? 
有没有一种方法可以结合构建类型和风格来获取构建变体，以便从最特定的res文件夹中获取资源？
Lets say I have 可以说我有
src/main
src/debug
src/flavor1
src/flavor2
In my src/main I have basic configuration. 在我的src/main我有基本配置。
In my src/flavor1 and src/flavor2 I have specific configurations and I want them to be overridden by values from src/debug . 在我的src/flavor1和src/flavor2我有特定的配置，我希望它们被src/debug值覆盖。 But flavor values are more specific and src/debug config is ignored. 但是风味值更具体，并且src/debug配置被忽略。
For example each flavor has @string/app_name . 例如，每种口味都有@string/app_name 。 Ie Flavor 1 App . 即Flavor 1 App 。 I want to override @string/app_name with Flavor 1 App Dev 我想用Flavor 1 App Dev覆盖@string/app_name
Is there any way to get effect I want? 有什么方法可以达到我想要的效果吗？
1 个解决方案
解决方案1
3 已采纳 2014-02-04 09:26:23
You can use these folders 您可以使用这些文件夹
main
java
res
flavor1
java
res
flavor1Debug
java
res
flavor1Release
java
res
flavor2
java
res
flavor2Debug
java
res
flavor2Release
java
res
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