inputVal上的Math.pow（）

Question

I don't know how to use the Math.pow() when I have 1 variable that gets my inputs which is inputVal . This is how I did it.

else if(pow == true){
    if(equation.indexOf('^') == inputVal){
        inputVal = inputVal.replace('^', '');
        input.innerHTML = Math.pow(inputVal);
    }else{
        input.innerHTML = 'Syntax Error';
        pow = false;
    }
}

I tried to do this on my own, and it doesn't work.

I've also tried this

else if(pow == true){
    input.innerHTML = Math.pow(inputVal);
}else{
    pow = false;
}

Answer 1

Presumably, your input value is of the form base^exponent . So, split the input on ^ to get an array of arguments and then call Math. pow () Math. pow () using the spread operator , ... ; eg:

 console.log("result: %o", Math.pow(..."2^3".split("^"))); 

Answer 2

Math.pow() needs 2 parameters. If your inputVal is aa^b format what you will need to do is

var piv = inputVal.indexOf("^");
var a = parseInt(inputVal.substring(0, piv));
var b = parseInt(inputVal.substring(piv+1));
input.innerHTML = Math.pow(a, b);

Please make sure your inputVal is a string. otherwise the string function wont work. the comments from conan is correct. you can try parseFloat or even Number() function according to your needs.