Python 3：以编程方式将十六进制数列表转换为二进制数

Question

I have a list of hex numbers as strings and I want to convert all of them to binary. I'm using Python 3. What's a good way to do this?

EDIT: The numbers are in the format '0x23051fb2' , ie they start with an 0x .

Answer 1

hexlist = ['0x23051fb2', '0xAB', '0xAC']
binlist = [bin(int(x, 16)) for x in hexlist]

Now if we do print(binlist) we get:

['0b100011000001010001111110110010', '0b10101011', '0b10101100']

Answer 2

lst = ['0x1A', '0xFF', 'FF']
print map(lambda x: bin(int(x, 16)), lst)

Output:

['0b11010', '0b11111111', '0b11111111']