std ::找到对象指针的向量

Question

I have a class A with a member which is a vector of object pointers of another class B

class A
{
    std::vector<B*> m_member_A

Now I want to perform a std::find on m_member_A . Eg if(std::find(m_member_A.begin(), m_member_A.end(), B_obj*) != m_member_A.end())

std::find doesn't make sense on such a vector. How do I achieve such a functionality?

How would it change if it were a vector of objects of B (not pointer)?

Answer 1

Vector works perfectly fine with std::find

auto result = std::find(m_member_A.begin(), m_member_A.end(), itemToFind);
if (result != m_member_A.end()) {
  // found it!
}

Or if you need to dereference the pointer:

auto result = std::find_if(m_member_A.begin(), m_member_A.end(), 
  [] (B* item) { 
    if (item == nullptr) return false; // may want to do something else here
    return *item == someValue;
  });
if (result != m_member_A.end()) {
  // found it!
}

Demo: http://ideone.com/jKCrG5

Answer 2

If you want to find a value pointer at by the pointer, instead of a given pointer, you can use std::find_if with a suitable functor:

struct Foo
{
  int i;
};

bool operator==(const Foo& lhs, const Foo& rhs) { return lhs.i == rhs.i; }

std::vector<Foo*> v = ....;

Foo f{42};

std::find_if(v.begin(), v.end(), [&f](const Foo* p) { return *p == f; });

Answer 3

If you want to compare values instead of comparing pointers, you might want to use std::find_if instead:

bool IsFoo (B* _item) {
    bool result = false;

    if ( _item != nullptr && _item->value == 1 ) //Whatever is your criteria
        result = true; 

    return result;
}

std::vector<B*> m_member_A;
B* instance = std::find_if (m_member_A.begin(), m_member_A.end(), IsFoo);