如何使用find + regex匹配文件并仅返回包含所述文件的唯一目录？

Question

This find command matches the files I'm searching for:

find / -type f -regextype sed -regex ".*/g\.[0-9]\{4\}.*"

How do I move to the next step of listing just the unique directory names that contain those files? (I don't need to display all the files.)

Answer 1

将输出传递给删除文件名的sed命令，然后使用uniq删除重复项：

find / -type f -regextype sed -regex ".*/g\.[0-9]\{4\}.*" | sed 's|/[^/]*$||' | uniq