Bash脚本：在for循环内填充一个数组

Question

I try to create an array that is filled up with some values. But i don't know how to do it. I tried something below but it didn't work.

My code:

i=0
for c in colors; do
array[$i]=$c
echo {$c[$i]}
i=`expr $i + 1`
done

note: "colors" is some kind of "ps -ef" command that returns a list of values. it has "blue,red,yellow" values for example.

colors= 'ps -ef | grep colors'

Answer 1

If your colors are coming in one-to-a-line, you're potentially losing information (dropping the distinction between spaces and newlines, expanding glob characters, etc) as soon as you expand the variable that stores them unquoted.

Don't do that. Instead, follow BashFAQ #1 :

colors=()
while IFS='' read -r color; do
    colors+=( "$color" )
done < <(get-color-list)

That's even more true if you only want, say, a specific column out of each line; read will do the column-splitting for you, making it easier to assign.

Answer 2

You can use this script to fill up the array in a loop:

array=()
for c in $colors; do
    array+=( "$c" )
done

OR even simpler:

array=( $(command) )