将列表作为几个参数传递

Question

I'm trying to use a list as arguments, using the :

>>> l = [1,2,3]
>>> print( *l )

I got an error :

File "<stdin>", line 1
t*
 ^
SyntaxError: invalid syntax

I'm using python 2.7 :

>>> import sys
>>> print sys.version
2.7.3 (default, Jan  2 2013, 13:56:14)
[GCC 4.7.2]

What am I missing ? Thank you ! :)

Answer 1

By default, print isn't a function in Python 2.7. To use the function instead of the statement in a given module, use a future statement:

from __future__ import print_function

This needs to go at the top of your file, before any code that isn't a future statement (or the module docstring), because the compiler needs to see future statements first to compile the rest of the module differently based on the future statement.

Answer 2

print is NOT a function in Python 2.7. It is a statement. So, you should do

print l           # [1, 2, 3]

If you want to use print as a function in Python 2.7, you should import print_function from __future__ , like this

from __future__ import print_function
l = [1,2,3]
print(l)          # [1, 2, 3]
print(*l)         # 1 2 3

Answer 3

如果要使用print作为函数，则必须使用__future__或将python升级到3+

Answer 4

Is this what you are searching for?

>>> l = [1, 2, 3]
>>> def x(*args):
...     print args[0]
...     print args
>>> x(*l)
1
(1, 2, 3)

If yes, take also a look at Arbitrary Argument Lists in the Python documenation.