将几个参数传递给脚本的更有效方法？

Question

My command line script takes several arguments including strings, ints, floats and lists, and it is becoming a bit tricky to do the call with all arguments:

python myscript.py arg1 arg2 arg3 ... argN

To avoid having to write all arguments in the command line I have created a text file with all arguments which I simply read line by line to collect arguments. This is working fine, but is this the best practice for doing this? Are there a more effective way?

Answer 1

You can use argpase module. Refer to the following links :)

https://pymotw.com/2/argparse

Dead simple argparse example wanted: 1 argument, 3 results

Answer 2

For me I think python getopt is the way to go.

#!/usr/bin/python

import sys, getopt

def main(argv):
   inputfile = ''
   outputfile = ''
   try:
      opts, args = getopt.getopt(argv,"hi:o:",["ifile=","ofile="])
   except getopt.GetoptError:
      print 'test.py -i <inputfile> -o <outputfile>'
      sys.exit(2)
   for opt, arg in opts:
      if opt == '-h':
         print 'test.py -i <inputfile> -o <outputfile>'
         sys.exit()
      elif opt in ("-i", "--ifile"):
         inputfile = arg
      elif opt in ("-o", "--ofile"):
         outputfile = arg
   print 'Input file is "', inputfile
   print 'Output file is "', outputfile

if __name__ == "__main__":
   main(sys.argv[1:])

Usage:

usage: test.py -i <inputfile> -o <outputfile>

It's easier to run when you have a name for the argument.

Ref: http://www.tutorialspoint.com/python/python_command_line_arguments.htm