[英]comparing character array and character pointer using strcmp
int main(void) {
char s[] = "ab";
char *s1 = "ab";
if(strcmp(s, s1))
printf("%d", 24);
else
printf("%d", 23);
return EXIT_SUCCESS;
}
Why it is giving 23 answer? 为什么给出23个答案?
This is because strcmp
returns 0
if strings are equal. 这是因为如果字符串相等,则strcmp
返回0
。 0
is treated as false
in C. 0
在C中被视为false
。
strcmp(string1, string2)
if Return value < 0 then it indicates string1 is less than string2
if Return value > 0 then it indicates string2 is less than string1
if Return value = 0 then it indicates string1 is equal to string2
strcmp
returns 0 if the given strings are equal, as in this case. 如果给定的字符串相等,则strcmp
返回0,在这种情况下。 0
is converted to false
, so the else
block is executed, printing 23
. 0
转换为false
,因此执行else
块,打印23
。
strcmp
on success returns 0
. 成功的strcmp
返回0
。 Hence if
will fail. 因此, if
失败。
Change if
statement as, 将if
语句更改为
if(strcmp(s , s1) == 0)
如果两个字符串比较相等,则strcmp
返回0。
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