comparing character array and character pointer using strcmp

Question

int main(void) {
    char s[] = "ab";
    char *s1 = "ab";

    if(strcmp(s, s1))
        printf("%d", 24);
    else
        printf("%d", 23);

    return EXIT_SUCCESS;
}

Why it is giving 23 answer?

Answer 1

This is because strcmp returns 0 if strings are equal. 0 is treated as false in C.

strcmp(string1, string2)

Return Value

if Return value < 0 then it indicates string1 is less than string2

if Return value > 0 then it indicates string2 is less than string1

if Return value = 0 then it indicates string1 is equal to string2  

Answer 2

strcmp returns 0 if the given strings are equal, as in this case. 0 is converted to false , so the else block is executed, printing 23 .

Answer 3

strcmp on success returns 0 . Hence if will fail.

Change if statement as,

if(strcmp(s , s1) == 0)

Answer 4

如果两个字符串比较相等，则strcmp返回0。