Comparing addresses of character array

Question

So it give me an error using if(argv[i]=="-o"). Is there a different function I can use.

Answer 1

You can't compare strings like this in C:

if(argv[i]=="-o")

That just compares the addresses of the character arrays.

What you need is:

if(strcmp(argv[i],"-o") == 0)

This actually runs through the 2 strings and returns 0 if all characters are the same.

Answer 2

The first loop tries to open all the parameters as files, so if a -o occurs before a filename, it will try to open the file "-o"

You are comparing a string with ==, which won't do what you are intending, as it only compares the pointers, not the string itself. try strcmp instead

If the -o is the last parameter you will get a memory fault, as when you find a -o, you then blindly read from argv[i+1], even if i=argc-1