[英]matlab find substring in cell array
I try to find arrays in my cell which have to part 'HA' in their names. 我试图在我的单元格中找到必须在其名称中包含“HA”的数组。 I found a function here but it does not work for my problem. 我在这里找到了一个功能,但它对我的问题不起作用。 My cell looks like this: 我的手机看起来像这样:
'HA1' 'HA1' 'HA1' 'HA1' 'HA1'
'HA2' 'HA2' 'HA2' 'HA2' 'HA2'
'HA3' 'HA3' 'HA3' 'HA3' 'HA3'
'HA4' 'HA4' 'HA4' 'HA4' 'HA4'
'HA5' 'HA5' 'HA5' 'HA5' 'HA5'
'HA6' 'HA6' 'HA6' 'HA6' 'HA6'
'HA7' 'HA7' 'HA7' 'HA7' 'HA7'
'HA8' 'WA1' 'WA1' 'WA1' 'WA1'
'HA9' 'WA2' 'WA2' 'WA2' 'WA2'
'HA10' 'WA3' 'WA3' 'WA3' 'WA3'
'HA11' 'WA4' 'WA4' 'WA4' 'WA4'
'DA1' 'WA5' 'WA5' 'WA5' 'WA5'
'DA2' [] [] [] 'WA6'
'DA3' [] [] [] 'WA7'
'DA4' [] [] [] 'WA8'
'DA5' [] [] [] 'WA9'
'DA6' [] [] [] 'WA10'
[] [] [] [] 'WA11'
[] [] [] [] 'WA12'
I tried this function: 我试过这个功能:
x = 'HA';
y = cellArray;
substrfind = @(x,y) ~cellfun(@isempty,strfind(y,x));
logicalArray = substrfind(x,y);
Im supposed to get a logical array as output which is really useful for my problem. 我应该得到一个逻辑数组作为输出,这对我的问题非常有用。 But instead I get this error message: " If any of the input arguments are cell arrays, the first must be a cell array of strings and the second must be a character array." 但我收到此错误消息:“如果任何输入参数是单元格数组,则第一个必须是字符串的单元格数组,第二个必须是字符数组。”
I do not understand what the error is because the first input y is a cell array and the second xa character. 我不明白错误是什么,因为第一个输入y是一个单元格数组,第二个是xa字符。
I hope you guys can help me with my problem! 我希望你们能帮助我解决我的问题! Thank you in anticipation! 谢谢你的期待! Best regards 最好的祝福
Suppose C
is your cell array. 假设C
是你的单元阵列。 Then one way to do what you want would be this: 然后一种方法来做你想要的是这样的:
>> C(cellfun('isempty', C)) = {''};
>> logicalArray = ~cellfun('isempty', strfind(C, 'HA'))
strfind
does not accept cell arrays of which some values are not strings. strfind
不接受某些值不是字符串的单元格数组。 Your cell array happens to have empty values, but of the wrong kind -- []
is double
, not char
. 你的单元格数组恰好有空值,但错误的类型 - []
是double
,而不是char
。 That is the reason you get that error. 这就是你得到这个错误的原因。
So, I simply replace every empty double
with the empty char ( ''
), and then use strfind
. 所以,我只需用空的char( ''
)替换每个空的double
,然后使用strfind
。
Another way around this problem: 解决此问题的另一种方法:
>> logicalArray = cellfun(@(x)~isempty(strfind(x,'HA')), C)
but that is a lot slower. 但那要慢得多。
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