[英]Constructor similar to std::map or std::vector in a class
I'm creating a class and I want to know how to create a constructor similar to the std::map
or std::vector
style. 我正在创建一个类,我想知道如何创建类似于
std::map
或std::vector
样式的构造函数。
std::map<std::string, std::string> map = {
{"foo", "bar"},
{"biz", "buz"},
{"bez", "boz"}
};
The difference is that I don't want my class to ask for types that wants to accept, just like std::map
does. 不同之处在于我不希望我的类要求接受类型,就像
std::map
一样。
std::map<std::string, std::string>
I want my class to accept that style of arguments: 我希望我的班级接受这种风格的论点:
{
{"foo", "bar"},
{"biz", "buz"},
{"bez", "boz"}
};
But with defined type. 但是有定义的类型。 (std::string, Typer)
(std :: string,Typer)
The 'Typer' is a class that I will insert as value on the std::map
. 'Typer'是一个我将在
std::map
上作为值插入的类。
If I understand your question correctly, you want a constructor taking std::initializer_list<std::pair<std::string, Typer>>
, like this: 如果我正确理解你的问题,你想要一个构造函数采用
std::initializer_list<std::pair<std::string, Typer>>
,如下所示:
struct Typer
{
std::string data;
Typer(const char *s) : data(s) {}
};
struct MyClass
{
MyClass(std::initializer_list<std::pair<std::string, Typer>> i)
: myMap(begin(i), end(i))
{}
std::map<std::string, Typer> myMap;
};
int main()
{
MyClass m = {
{"foo", "bar"},
{"biz", "buz"},
{"bez", "boz"}
};
}
typedef std::map<std::string, Typer> MyType;
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