如何将图像背景放在变量中？

Question

It's kind of a stupid question, but I need to store a div with a background image in a variable. My problem arises from the use of " and ' .

This is obviously wrong:

$var = "<div style="background-image:url('bg.png');">";

I have also tried these methods but none worked:

$var = "<div style='"."background-image:url('bg.png');".'">";

$var = "<div style='";
$var = $var."background-image:url('bg.png');";
$var = $var."'>";

Does anyone know how I can make it work?

Thanks.

Answer 1

You can either use single quotes or escape double quotes to avoid any problems

$var = "<div style=\"background-image:url('bg.png');\">";

Or

$var = '<div style="background-image:url(\'bg.png\');">';

Answer 2

It's the double quotes that's messing with you. You would either have to do \\" or just use single quotes (acceptable in PHP, and more convenient with HTML):

$var = '<div style="background-image:url(\'bg.png\');">';

With double quotes:

$var = "<div style=\"background-image:url('bg.png');\">";

This is valid and will work. Now just use echo $var; to show it.