Scala获取列表中的所有元素小于特定值

Question

I'm trying to get a partition of a list based on the values less than some parameter I'm passing into the function. I'm thinking of using the map function somehow to apply a function in order to make this new list, but I don't see how to do so:

exampleList.map(s => s<10)

For instance here, I want to get all the elements of the list that are less than 10, but I feel like this would just return a list of booleans. I know I can also use for comprehension with yield or maybe reduce, but I'm unsure of how to do so. (My Scala knowledge is limited)

Thanks in advance for any help

Answer 1

Use the filter method:

exampleList.filter(s => s < 10)

Using lambda syntactic sugar:

exampleList.filter(_ < 10)

Using list comprehensions

for (s <- exampleList; if s < 10) yield s

The Seq API is a good place to start if you want to expand your knowledge of the collection API:

http://www.scala-lang.org/api/current/index.html#scala.collection.Seq