读取由换行符分隔的文本文件。 Unix上的C ++

Question

Ok I have tried many different suggestions on the www, and came up flat with all the examples. This is such a simple thing that is not working for me it is frustrating! I have attached the file that I need to read into a data structure. In the example I am just printing it to the screen. This following code has worked for me before, but now isn't. I have tried in visual studios, and on unix, and neither are running it. I ultimately need it to run on unix.

Can anyone tell me why this is not working, or suggest a better way to read in my file? Example file:

word
book
programming

Here is my function to read in the file.

#include "stdafx.h"
#include <fstream>
#include <iostream>
#include <string>
#include "words.txt"
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
ifstream file;
string line;

file.open("words.txt");
if(file.is_open()){
    while(getline(file, line)){
        getline(file, line);
        cout << line <<endl;
    }
}
file.close();



return 0;
}

Thank you.

the file but is throwing errors about delimiters. For example in unix running with g++ :

wordlist2.txt: 498841:1: error: missing terminating ' character
  incumbent's
  ^
wordlist2.txt:498875:13 warning: missing terminating ' character [enabled by default] 
  at your wits' end
  ^

And in visual studios:

  Error 2   error C4430: missing type specifier - int assumed. Note: C++ does                not support default-int    
  Error 14  error C2146: syntax error : missing ';' before identifier 'mouse'

Answer 1

while (!file.eof())

Is not a good idea. Write the following instead:

while (getline(file, line)) {
    cout << line << endl;
}

You certainly don't want to

#include "words.txt"

Remove this line!!