将一维数组打印为两个二维数组

Question

I'm trying to create a method that takes a one dimensional array and prints it out as a two dimensional array, but as square as possible so it looks nice. I've tried creating for loops to do this, but how would you figure out how many rows and columns there are? Could someone give me the logic in how to make one, so I can use that to create my own? An explanation would be lovely.

Answer 1

This will make a new array that is square and big enough to house all the elements of the old array. It takes the square root of the original array's length and rounds up.

int size = (int)Math.ceil(Math.sqrt(oldArray.length));
int[][]newArray = new int[size][size];

Answer 2

Example:

array =    |1 2 3|
           |4 5 6|
           |7 8 9| (3*3)

Make a 1D array

int array1 = new int[3*3];

Or you can get length of the array

For row length: int row = array.length;

For column length: int column = array[0].length;

and then int array1 = new int[row*column];

Now iterate over array and copy all elements of array into array1 .

         _________________
array1 = |1|2|3|4|5|6|7|8|9|

Now don't ask me for code.

Answer 3

This method will print the elements in your one-dimensional array as close as possible to a square pattern on the console output. It places tabs in between elements to line them up on each row.

private void printMyArray(String[]  onDimensionalArray) {
    int cols = (int) Math.floor(Math.sqrt(onDimensionalArray.length));
    int currentCol = 0;
    for(String element : onDimensionalArray) {
        System.out.print(element + "\t");
        if(currentCol >= cols) {
            System.out.println("");
            currentCol = 0;
        }
        else {
            currentCol++;
        }
    }
}

Answer 4

check this out

int array2d[][] = new int[10][3];


for(int i=0; i<10;i++)
for(int j=0;j<3;j++)
   array2d[i][j] = array1d[(j*10) + i];