正则表达式以查找值并以PHP返回

Question

I've been trying to figure this out for 2 hours now with no success. Its a bit complicated for me i guess. I am trying to parse a script file in PHP and return some values to the user. The ones i want are like this:

_ value = object runFunction blah blah blah

Basically what i want is (in an algorithm):

• IF case-insensitive runFunction is found in the line (because it might be runfunction)
• AND the line starts with _ (underscore) (or if possible before the = there is a value that starts with _ to be sure of the result)
• THEN return that underscore value before the = to me.

Usually 99.9% the format is like this...But there are small cases it can be like this:

_ value = _object runFunction blah blah blah (in case the _ after the = messes things up).

Any help here :) ? Thanks

Answer 1

try something like:

$str = 'YOUR FILE CONTENTS HERE';
$match = preg_match_all('/(_[a-zA-Z0-9_]+) ?= ?[a-zA-Z0-9_]+ runFunction/s',$str,$matches);

var_dump($matches);

you'll probably need to add the multiline flag.

Answer 2

How about

if (preg_match('/^_([^=]+?)(?=\s*=).*runfunction/im', $subject, $regs)) {
    $result = $regs[1];
} else {
    $result = "";
}

You can exclude the initial "start" anchor is your underscore might not be at the beginning of the line

Here is the regex by itself. The results are in capturing group 1

^_([^=]+?)(?=\s*=).*runfunction

The regex look for beginning of line match the first underscore capture everything that is not an '=' into capturing group 1 provided it is followed by 0 or more spaces and an equal sign. then capture everything up to a runfunction.

Case insensitive and multiline options need to be set

If the first underscore does not need to be at the beginning of the line, eliminate the anchor.