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使用2个变量将数据框从宽变换为长

[英]Convert data frame from wide to long with 2 variables

I have the following wide data frame (mydf.wide): 我有以下宽数据框(mydf.wide):

DAY JAN F1  FEB F2  MAR F3  APR F4  MAY F5  JUN F6  JUL F7  AUG F8  SEP F9  OCT F10 NOV F11 DEC F12
1   169 0   296 0   1095    0   599 0   1361    0   1746    0   2411    0   2516    0   1614    0   908 0   488 0   209 0
2   193 0   554 0   1085    0   1820    0   1723    0   2787    0   2548    0   1402    0   1633    0   897 0   411 0   250 0
3   246 0   533 0   1111    0   1817    0   2238    0   2747    0   1575    0   1912    0   705 0   813 0   156 0   164 0
4   222 0   547 0   1125    0   1789    0   2181    0   2309    0   1569    0   1798    0   1463    0   878 0   241 0   230 0

I want to produce the following "semi-long": 我想生产以下“半长”:

DAY variable_month value_month value_F
1 JAN 169 0

I tried: 我试过了:

library(reshape2)
mydf.long <- melt(mydf.wide, id.vars=c("YEAR","DAY"), measure.vars=c("JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"))

but this skip the F variable and I don't know how to deal with two variables... 但这跳过F变量,我不知道如何处理两个变量......

This is one of those cases where reshape(...) in base R is a better option. 这是基础R中的reshape(...)是更好的选择的情况之一。

months    <- c(2,4,6,8,10,12,14,16,18,20,22,24)   # column numbers of months
F         <- c(3,5,7,9,11,13,15,17,19,21,23,25)   # column numbers of Fn
mydf.long <- reshape(mydf.wide,idvar=1,
             times=colnames(mydf.wide)[months],
             varying=list(months,F),
             v.names=c("value_month","value_F"),
             direction="long")
colnames(mydf.long)[2] <- "variable_month"
head(mydf.long)
#       DAY variable_month value_month value_F
# 1.JAN   1            JAN         169       0
# 2.JAN   2            JAN         193       0
# 3.JAN   3            JAN         246       0
# 4.JAN   4            JAN         222       0
# 1.FEB   1            FEB         296       0
# 2.FEB   2            FEB         554       0

You can also do this with 2 calls to melt(...) 您也可以通过2次调用来melt(...)

library(reshape2)
months    <- c(2,4,6,8,10,12,14,16,18,20,22,24)   # column numbers of months
F         <- c(3,5,7,9,11,13,15,17,19,21,23,25)   # column numbers of Fn
z.1 <- melt(mydf.wide,id=1,measure=months,
            variable.name="variable_month",value.name="value_month")
z.2 <- melt(mydf.wide,id=1,measure=F,value.name="value_F")
mydf.long <- cbind(z.1,value_F=z.2$value_F)
head(mydf.long)
#   DAY variable_month value_month z.2$value_F
# 1   1            JAN         169           0
# 2   2            JAN         193           0
# 3   3            JAN         246           0
# 4   4            JAN         222           0
# 5   1            FEB         296           0
# 6   2            FEB         554           0

melt() and dcast() are available from the reshape2 and data.table packages. melt()dcast()可以从reshape2data.table包中获得。 The recent versions of data.table allow to melt multiple columns simultaneously . 最新版本的data.table允许同时melt多个列 The patterns() parameter can be used to specify the two sets of columns by regular expressions: patterns()参数可用于通过正则表达式指定两组列:

library(data.table)   # CRAN version 1.10.4 used
regex_month <- toupper(paste(month.abb, collapse = "|"))
mydf.long <- melt(setDT(mydf.wide), measure.vars = patterns(regex_month, "F\\d"),
                  value.name = c("MONTH", "F"))
# rename factor levels
mydf.long[, variable := forcats::lvls_revalue(variable, toupper(month.abb))][]
  DAY variable MONTH F 1: 1 JAN 169 0 2: 2 JAN 193 0 3: 3 JAN 246 0 4: 4 JAN 222 0 5: 1 FEB 296 0 ... 44: 4 NOV 241 0 45: 1 DEC 209 0 46: 2 DEC 250 0 47: 3 DEC 164 0 48: 4 DEC 230 0 DAY variable MONTH F 

Note that "F\\\\d" is used as regular expression in patterns() . 请注意, "F\\\\d"用作patterns()正则表达式。 A simple "F" would have catched FEB as well as F1 , F2 , etc. producing unexpected results. 一个简单的"F"会捕获FEB以及F1F2等,产生意想不到的结果。

Also note that mydf.wide needs to be coerced to a data.table object. 另请注意, mydf.wide需要强制转换为data.table对象。 Otherwise, reshape2::melt() will be dispatched on a data.frame object which doesn't recognize patterns() . 否则,将在不识别patterns()的data.frame对象上调度reshape2::melt() patterns()

Data 数据

library(data.table)
mydf.wide <- fread(
"DAY JAN F1  FEB F2  MAR F3  APR F4  MAY F5  JUN F6  JUL F7  AUG F8  SEP F9  OCT F10 NOV F11 DEC F12
  1   169 0   296 0   1095    0   599 0   1361    0   1746    0   2411    0   2516    0   1614    0   908 0   488 0   209 0
  2   193 0   554 0   1085    0   1820    0   1723    0   2787    0   2548    0   1402    0   1633    0   897 0   411 0   250 0
  3   246 0   533 0   1111    0   1817    0   2238    0   2747    0   1575    0   1912    0   705 0   813 0   156 0   164 0
  4   222 0   547 0   1125    0   1789    0   2181    0   2309    0   1569    0   1798    0   1463    0   878 0   241 0   230 0",
data.table = FALSE)

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