[英]MySQL Select the rows having same column value
I need to obtain the rows which having same column value from the following table, I tried it the following way, but it gives me a single row only. 我需要从下表中获取具有相同列值的行,我按照以下方式尝试,但它只给我一行。
select *
from employee e
group by e.empsalary
having count(e.empsalary) > 1
Table employee 表员工
Please suggest me a way. 请建议我一个方法。
You should be able to accomplish this by joining the table to itself: 您应该能够通过将表连接到自身来实现此目的:
SELECT
a.*
FROM
employee a
JOIN employee b
ON a.empsalary = b.empsalary
AND a.empid != b.empid
Use an inner join to join with your query posted. 使用内部联接加入您发布的查询。
select A.* from employee A
inner join (
select empsalary
from employee
group by empsalary
having count(*) > 1
) B ON A.empsalary = B.empsalary
Something like this perhaps 或许这样的事情
SELECT * FROM employee a
WHERE EXISTS (
SELECT 1 FROM employee b
WHERE a.empsalary = b.empsalary
AND a.empid <> b.empid
);
Demo - http://sqlfiddle.com/#!2/d75d9/4 演示 - http://sqlfiddle.com/#!2/d75d9/4
select * from employee where empsalary IN(select empsalary from employee group by empsalary having count(empsalary ) > 1)
Try This.It gives 2 rows as you want. 试试This.It你想要的两行。
Demo: http://sqlfiddle.com/#!2/d75d9/6 演示: http : //sqlfiddle.com/#!2/d75d9/6
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