MySQL选择具有相同列值的行

Question

我需要从下表中获取具有相同列值的行，我按照以下方式尝试，但它只给我一行。

select *
from employee e
group by e.empsalary
having count(e.empsalary) > 1

表员工

请建议我一个方法。

Answer 1

您应该能够通过将表连接到自身来实现此目的：

SELECT
    a.*
FROM
    employee a
    JOIN employee b
        ON a.empsalary = b.empsalary
        AND a.empid != b.empid

Answer 2

使用内部联接加入您发布的查询。

select A.* from employee A
inner join (
  select empsalary
  from employee 
  group by empsalary
  having count(*) > 1
) B ON A.empsalary = B.empsalary

Answer 3

或许这样的事情

SELECT * FROM employee a
WHERE EXISTS (
    SELECT 1 FROM employee b
    WHERE a.empsalary = b.empsalary
    AND a.empid <> b.empid
);

演示 - http://sqlfiddle.com/#!2/d75d9/4

Answer 4

select * from employee where empsalary IN(select empsalary from employee  group by empsalary having count(empsalary ) > 1)

试试This.It你想要的两行。

演示： http ： //sqlfiddle.com/#！2/d75d9/6