[英]Remove elements in DOM
can some one show how to work with few elements in DOM and move them from one block to another, I need use jQuery, for example I have this structure 可以有人展示如何使用DOM中的少数元素并将它们从一个块移动到另一个块,我需要使用jQuery,例如我有这个结构
<div class="block">
<div class="block_left">
<div class="title">title 1</div>
<div class="image">image 1 for title 1</div>
</div>
<div class="block_right">
</div>
</div>
<div class="block">
<div class="block_left">
<div class="title">title 2</div>
<div class="image">image 2 for title 2</div>
</div>
<div class="block_right">
</div>
</div>
<div class="block">
<div class="block_left">
<div class="title">title 3</div>
<div class="image">image 3 for title 3</div>
</div>
<div class="block_right">
</div>
</div>
<div class="block">
<div class="block_left">
<div class="title">title 4</div>
<div class="image">image 4 for title 4</div>
</div>
<div class="block_right">
</div>
</div>
I was trying to use jQuery .each()
but not that I need. 我试图使用jQuery .each()
但不是我需要的。 In result I need this: 结果我需要这个:
<div class="block">
<div class="block_left">
<div class="title">title 1</div>
</div>
<div class="block_right">
<div class="image">image 1 for title 1</div>
</div>
</div>
<div class="block">
<div class="block_left">
<div class="title">title 2</div>
</div>
<div class="block_right">
<div class="image">image 2 for title 2</div>
</div>
</div>
<div class="block">
<div class="block_left">
<div class="title">title 3</div>
</div>
<div class="block_right">
<div class="image">image 3 for title 3</div>
</div>
</div>
<div class="block">
<div class="block_left">
<div class="title">title 4</div>
</div>
<div class="block_right">
<div class="image">image 4 for title 4</div>
</div>
</div>
How do I remove elements? 如何删除元素? Thanks 谢谢
$(".image").each(function() {
$(this).parent().parent().find(".block_right").append($(this));
});
Try that code, should work! 尝试该代码,应该工作!
Goodluck. 祝好运。
One possible solution with .each()
: .each()
一种可能解决方案:
$('.block .image').each(function() {
$(this).closest('.block').find('.block_right').append(this);
});
DEMO: http://jsfiddle.net/6afBy/ 演示: http : //jsfiddle.net/6afBy/
Try to use appendTo() here: 尝试在这里使用appendTo() :
$('.block_left .image').each(function() {
$(this).appendTo($(this).parent().next());
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.