Angular 5删除特定的DOM元素

Question

I have a small issue that I can't figure out how to do. I am just learning Angular / Typescript and I can't figure out how I could remove some DOM elements. I have some auto generated content, that has specific CSS classes. Unfortunately The objects are generated somewhere else and I cannot configure them in any way so I cannot add any ngIf or anything else on that content, that would simplify my work... I just have to use them. What I want to achieve is something like this( jQuery version):

$("#button").click(function() {
    $('.fc-oss').toggle();
 });

I have a toggle and I want to attach an event to it that when it's being activated, it hides/ shows all elements with that specific type from the view. I am trying to achieve this in angular without jQuery but with little success. Any ideas on how I might be able to achieve this ?

Answer 1

您可以使用*ngIf="boleanVar" ，在您的ts中使用'boleanVar = true'初始化它并添加<br>< button (click)="boleanVar = !boleanVar"> Toggle visibility</button>

Answer 2

In Angular you can use direct access to DOCUMENT.

import { Inject, Injectable } from '@angular/core';
import { DOCUMENT } from '@angular/platform-browser';

@Injectable()
export class MyService {
  constructor(@Inject(DOCUMENT) private document: any) {}
}

Having this you can access your element and define some logic to it

let element = this.document.getElementbyClassName('fc-oss');
element.style.display = element.style.display === 'none' ? 'block' : 'none';

Answer 3

You can use the ngif directive for that.

@Component({
  selector: 'ng-if-simple',
  template: `
    <button (click)="show = !show">{{show ? 'hide' : 'show'}}</button>
    show = {{show}}
    <br>
    <div *ngIf="show">Text to show</div>
`
})
class NgIfSimple {
  show: boolean = true;
}

According to the value of the variable show the div element will toggle view.