如何使用sed删除所有行，直到第一列中的第一个匹配项？

Question

How to use sed to remove all lines until first match in first column? The result should keep the last three lines.

file

1fff
2ddd
3zzz

 TestXXX
 TestXXX
Test        XXX
Mike
Charly

sed -i '/Test/' file

Answer 1

sed -n '/^Test/,$p' oldfile > newfile

Answer 2

I'd use the .. operator in perl
it toggles on when the first condition is met
and toggles off when the second is met.

(I've added ^ because you said you wanted the start of the line)

perl -nle 'print if /^Test/..0' file

LATE EDIT: on second reading, the ..0 isn't clear. it is the line number, and since line 0 will not be reached after "Test" it will never happen.

Answer 3

sed -n '/^Test/,$ p' YourFile

仅在测试后直到结束才打印

Answer 4

这可能对您有用（GNU sed）：

sed -i '/^Test/,$!d' file