如何仅删除文件的所有行中的前两个前导空格

Question

my input file is like

  *CONTROL_ADAPTIVE
  $  adpfreq    adptol    adpopt    maxlvl    tbirth    tdeath     lcadp    ioflag
        0.10     5.000         2         3       0.0       0.0         0         0

I JUST want to remove the leading 2 spaces in all the lines.

I used

sed "s/^[ \t]*//" -i inputfile.txt

but it deletes all the space from all the lines.. I just want to shift the complete text in files to two position to left.

Any solutions to this?

Answer 1

You can specify that you want to delete two matches of the character set in the brackets:

sed -r -i "s/^[ \t]{2}//" inputfile.txt

See the output:

$ sed -r "s/^[ \t]{2}//" file
*CONTROL_ADAPTIVE
$  adpfreq    adptol    adpopt    maxlvl    tbirth    tdeath     lcadp    ioflag
      0.10     5.000         2         3       0.0       0.0         0         0