[英]How do you project a generic list into a dictionary?
Is there a simple, LINQ-only way to project a generic collection into a Dictionary, something which would eliminate the foreach in the following code block: 是否有一种简单的LINQ方法将泛型集合投影到Dictionary中,这将消除以下代码块中的foreach:
Dictionary<int, Player> _rankedPlayers = new Dictionary<int,Player>();
List<Player> rankedPlayers = Player.GetPlayers(Globals.FOOString, seasonCode);
int i = 1;
foreach (Player targetPlayer in rankedPlayers)
{
_rankedPlayers.Add(i, targetPlayer);
}
You are looking for ToDictionary
method 您正在寻找
ToDictionary
方法
var _rankedPlayers = Player.GetPlayers(Globals.FOOString, seasonCode)
.Select((item, index) => new { item, index })
.ToDictionary(x => index, x => x.item);
You can use the overload method of Enumerable.Select
that produces an index of the element and project it into a dictionary using Enumerable.ToDictionary
: 您可以使用
Enumerable.Select
的重载方法生成元素的索引,并使用Enumerable.ToDictionary
其投影到字典中:
var rankedPlayers = Player.GetPlayers(Globals.FOOString, seasonCode)
.Select((item, index) => Tuple.Create(item, index))
.ToDictionary(item => item.Item1 + 1, item => i.Item2);
If your player list is too long, you might not feel comfortable creating a lot of Tuple
instances and use an external index: 如果您的播放器列表太长,您可能
Tuple
创建大量的Tuple
实例并使用外部索引:
var i = 0;
var rankedPlayers = Player.GetPlayers(Globals.FOOString, seasonCode)
.ToDictionary(i => ++i, item => item.Item2);
Although this approach creates a new class for the closure over i
. 虽然这种方法为
i
封闭创造了一个新的类。
If this is still too much for you, you can create your own extension: 如果这对您来说仍然太多,您可以创建自己的扩展:
public static class MyExtensions
{
public static Dictionary<int, TSource> ToDictionary<TSource>(
this IEnumerable<TSource> source)
{
var dictionary = new Dictionary<int, TSource>();
var i = 0;
foreach(var item in source)
{
dictionary.Add(++i, item);
}
return dictionary;
}
}
But if you're using it only once, I would do it just like you did. 但如果你只使用它一次,我会像你一样。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.