是否可以在 C++ 中将类作为函数的参数传递

Question

Here is some pseudo code of what I would like to do:

void thing (storedClassArg){
    virtualClass<x,y> in1 = new storedClassArg<x,y>;
    virtualClass<x,z> in2 = new storedClassArg<x,z>;
}
 
main:
storedClass;
if( inputThingy)
    storedClass = type1;
else
    storedClass = type2;
thing(storedClass);

Answer 1

Short answer: no.

You can't pass a class as an argument to a function. You can only pass a value . A value refers to either an object or a function.

You can pass a class as an argument to a template. However, template arguments must be determined at compile-time, not run-time.

C++ provides run-time polymorphism only through inheritance. If you want to create an object whose type will not be known until run-time, what you can do is to make all possible types you might want to create derived classes of a common base.

Even still, you can't use the type itself , that you want to create, as an argument to a function. You'll have to pass in some other value and then branch on that to determine which type you want to create at run-time.