为函数分配的参数太多了？

Question

I define a variable

wchar_t path[256];

Then I try to get the strlen() of this variable

strlen(path);

Error is strlen() too many arguments?

I don't understand, I am only passing 1 argument to strlen() and path is simple a char of size WORD that can span up to 256 characters?

What is the issue here? How can I circumvent it?

SOLVED!

To get around this I simply type casted the sPath wchar_t as a (const BYTE *) therefore it allowed me to read in ASCII which told the strlen() function to stop counting when it hits zero. Works now.

Answer 1

您可以使用wcslen函数（在头文件<wchar.h>定义），它将const wchar_t *str作为参数，而strlen需要一个const char *str 。

Answer 2

strlen() looks for a '\\0' in the supplied string. Which is a null terminating string. If you pass it an uninitialized string it may look forever because who knows whats in the memory before you put something there. Which to continue means strlen() looks till it finds '\\0' which if there is no '\\0' it won't stop it'll read all the memory it can, should produce a endless loop.

Try putting:

char path[256] = {"test"};

Pass that, it auto null terminates in that case.