格式参数过多（printf 函数）

Question

Keep getting the following warning: “too many arguments for format” for the printf function below. Do not know what is causing this warning. I provided the type values of pos and str_pos along with the printf function. I excluded all other code as I did not think it was necessary for this question.

int pos;
char str_pos;
printf("The character at index %d is %c",pos,str_pos, "\n");

Answer 1

The corect way of writing that printf() statement would be

printf("The character at index %d is %c\n", pos, str_pos);

You need to change

• “ to " s.
• Use the format string correctly, including the newline.
• use pos and string_pos as the argument (not part of the format string itself), in the variadic list.

Also, I presume that variables are initialized before you're printing them.