PHP：从数据库中选择

Question

thank you for reading. I'm having a little problem with the next sentence:

$nats = mysql_query("SELECT id,name FROM reportSatus WHERE reportId = ". $_POST['id']);
$rnat = mysql_fetch_array($nats);

With print_r($rnat) :

Array(
[0] => 1
[id] => 1
[1] => Poca contaminacion
[name] => Poca contaminacion
[2] => 1
[reportId] => 1)

But in the database with the same sentence is:

id            name
1       Poca contaminacion
2       Mucha contaminacion

Any idea what can it be? Thank you in advance ~

Answer 1

try :

echo '<table><tr><th>id</th><th>name</th></tr>';
while ($row = mysql_fetch_assoc($nats)) {
    echo "<tr><td>{$row['id']}</td><td>{$row['name']}</td></tr>";
}
echo '</table>';

Answer 2

From documentation

Returns an array of strings that corresponds to the fetched row, or FALSE if there are no more rows. The type of returned array depends on how result_type is defined. By using MYSQL_BOTH (default), you'll get an array with both associative and number indices. Using MYSQL_ASSOC, you only get associative indices (as mysql_fetch_assoc() works), using MYSQL_NUM, you only get number indices (as mysql_fetch_row() works).

That's actually the way it works, if you need more rows to be returned you will need to loop throw the records

while($rnat = mysql_fetch_array($nats))
{
    //print here
}